
Since the triangles are similar, the ratio BC to AB equals the ratio B'C' to AB'. But AB equals 1. Hence,
BC = B'C' / AB'
but BC = sin A, so
sin A = B'C' / AB'
This result is most easily remembered as the sine of an angle in a right triangle equals the opposite side divided by the hypotenuse: sin= opp/hyp.
BC = B'C' / AB'
but BC = sin A, so
sin A = B'C' / AB'
This result is most easily remembered as the sine of an angle in a right triangle equals the opposite side divided by the hypotenuse: sin= opp/hyp.
No comments:
Post a Comment